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{&/x!:\2+!_x^1%2}

The braces around an expression denote a function. Because this
function contains a single variable, `x`

, it is a monadic
function or a *monad*. When typing in the above code at the
Klong prompt, the interpreter will respond `:monad`

.

You can apply the function to a value, say 251, using the Apply
(`@`

) verb, e.g.:

`{&/x!:\2+!_x^1%2}@251`

Expressions evaluate from the right to the left, so the first thing
the function does is *1 Divide 2*, giving 0.5:

`{&/x!:\2+!_x^1%2}@251`

The next operation is *x Power (1 Divide 2)*.
`x ^{1/2}` is the square root of

`{&/x!:\2+!_x^1%2}@251`

*Floor* (`_`

) then floors (rounds toward −infinity)
that value. So `_x^1%2`

is *Floor (x Power (1 Divide 2))*,
in this case the floor of the square root of 251.

`{&/x!:\2+!_x^1%2}@251`

Enumerate (`!`

) creates a vector containing all integers
from zero up to, but not including, that value. In this case,
`!_251^1%2`

= `!_15.84...`

=
`!15`

= `[0 ... 14]`

(a vector of the numbers
from 0 to 14).

`{&/x!:\2+!_x^1%2}@251`

A number plus a vector gives a new vector with the number added to each
of its elements, so `2+`

adds 2 to each element from the
previous step: `2+[0 ... 14]`

= `[2 ... 16]`

.

`{&/x!:\2+!_x^1%2}@251`

`!:\`

is a combination of the verb `!`

(Remainder)
and the adverb `:\`

(Each-Left). *x Remainder-Each-Left*
applies Remainder to each element of the previous step (`v`

) with
x as its left operand. It creates a new vector containing
`(x!v`

, i.e.:
_{0}),(x!v_{1}),...`(251!2),(251!3),(251!4),(251!5)...`

=
`(1),(2),(3),(1),...`

= `[1 2 3 1 ...]`

.

`{&/x!:\2+!_x^1%2}@251`

`&/`

is a combination of Min and Over. Min returns the
minimum of two numbers and Over folds Min over a vector, so Min-Over
returns the minimum of a vector:

`{&/x!:\2+!_x^1%2}@251`

In this case, the minimum of the vector is 1, because 1 is the smallest remainder obtained by dividing 251 by 2..16. In other words, 251 is prime.

If we had applied the function to a non-prime number, like 253, at least one of the elements of the vector would have divided that number with a remainder of 0, so the result of the function would also be 0.

{&/x!:\2+!_x^1%2}@253

Of course, the prime function is sufficiently complex to bind it
to a name using Define (`::`

):

`prime::{&/x!:\2+!_x^1%2}`

You can then use the function application syntax to apply it to some values:

prime::{&/x!:\2+!_x^1%2} prime(251) prime(253)

Of course, the `@`

operator would also work:

prime@251

BTW, the `prime`

function only works for values greater than
two. What will it return for 0, 1, and 2? Why?